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44=5h+h^2
We move all terms to the left:
44-(5h+h^2)=0
We get rid of parentheses
-h^2-5h+44=0
We add all the numbers together, and all the variables
-1h^2-5h+44=0
a = -1; b = -5; c = +44;
Δ = b2-4ac
Δ = -52-4·(-1)·44
Δ = 201
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-\sqrt{201}}{2*-1}=\frac{5-\sqrt{201}}{-2} $$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+\sqrt{201}}{2*-1}=\frac{5+\sqrt{201}}{-2} $
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